Base | Representation |
---|---|
bin | 11101010001111100010… |
… | …010111000101101010001 |
3 | 21010100122210121201110122 |
4 | 131101330102320231101 |
5 | 230431320241121202 |
6 | 4140205413240025 |
7 | 265241312655254 |
oct | 35217422705521 |
9 | 7110583551418 |
10 | 2012130020177 |
11 | 706380a38552 |
12 | 285b6a333015 |
13 | 1179876208c4 |
14 | 6d55d87509b |
15 | 37517d829a2 |
hex | 1d47c4b8b51 |
2012130020177 has 2 divisors, whose sum is σ = 2012130020178. Its totient is φ = 2012130020176.
The previous prime is 2012130020141. The next prime is 2012130020267. The reversal of 2012130020177 is 7710200312102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1854501963601 + 157628056576 = 1361801^2 + 397024^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012130020177 - 210 = 2012130019153 is a prime.
It is a super-2 number, since 2×20121300201772 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2012130020377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006065010088 + 1006065010089.
It is an arithmetic number, because the mean of its divisors is an integer number (1006065010089).
Almost surely, 22012130020177 is an apocalyptic number.
It is an amenable number.
2012130020177 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012130020177 is an equidigital number, since it uses as much as digits as its factorization.
2012130020177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1176, while the sum is 26.
Adding to 2012130020177 its reverse (7710200312102), we get a palindrome (9722330332279).
The spelling of 2012130020177 in words is "two trillion, twelve billion, one hundred thirty million, twenty thousand, one hundred seventy-seven".
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