Base | Representation |
---|---|
bin | 10010101111010100… |
… | …101110001101000011 |
3 | 1220221021210122221010 |
4 | 102233110232031003 |
5 | 312202024022430 |
6 | 13124341332003 |
7 | 1311424230240 |
oct | 225724561503 |
9 | 56837718833 |
10 | 20121314115 |
11 | 8595a59121 |
12 | 3a96707003 |
13 | 1b88871a36 |
14 | d8c4645c7 |
15 | 7cb730cb0 |
hex | 4af52e343 |
20121314115 has 16 divisors (see below), whose sum is σ = 36793260288. Its totient is φ = 9198314976.
The previous prime is 20121314113. The next prime is 20121314117. The reversal of 20121314115 is 51141312102.
It is an interprime number because it is at equal distance from previous prime (20121314113) and next prime (20121314117).
It is not a de Polignac number, because 20121314115 - 21 = 20121314113 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a junction number, because it is equal to n+sod(n) for n = 20121314091 and 20121314100.
It is not an unprimeable number, because it can be changed into a prime (20121314113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 95815677 + ... + 95815886.
It is an arithmetic number, because the mean of its divisors is an integer number (2299578768).
Almost surely, 220121314115 is an apocalyptic number.
20121314115 is a deficient number, since it is larger than the sum of its proper divisors (16671946173).
20121314115 is a wasteful number, since it uses less digits than its factorization.
20121314115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 191631578.
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 20121314115 its reverse (51141312102), we get a palindrome (71262626217).
The spelling of 20121314115 in words is "twenty billion, one hundred twenty-one million, three hundred fourteen thousand, one hundred fifteen".
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