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2012200110281 is a prime number
BaseRepresentation
bin11101010010000000011…
…110010000100011001001
321010100211200111200000102
4131102000132100203021
5230431441212012111
64140220355415145
7265243123505504
oct35220036204311
97110750450012
102012200110281
11706407560259
12285b898b44b5
13117998cc143a
146d568cbc13b
153751e0ca13b
hex1d4807908c9

2012200110281 has 2 divisors, whose sum is σ = 2012200110282. Its totient is φ = 2012200110280.

The previous prime is 2012200110211. The next prime is 2012200110359. The reversal of 2012200110281 is 1820110022102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1071463063225 + 940737047056 = 1035115^2 + 969916^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2012200110281 is a prime.

It is a super-2 number, since 2×20122001102812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2012200110211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006100055140 + 1006100055141.

It is an arithmetic number, because the mean of its divisors is an integer number (1006100055141).

Almost surely, 22012200110281 is an apocalyptic number.

It is an amenable number.

2012200110281 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012200110281 is an equidigital number, since it uses as much as digits as its factorization.

2012200110281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 2012200110281 its reverse (1820110022102), we get a palindrome (3832310132383).

The spelling of 2012200110281 in words is "two trillion, twelve billion, two hundred million, one hundred ten thousand, two hundred eighty-one".