Base | Representation |
---|---|
bin | 11101010010000000100… |
… | …110010001011100001001 |
3 | 21010100211211110101202211 |
4 | 131102000212101130021 |
5 | 230431442231223311 |
6 | 4140220512425121 |
7 | 265243150405336 |
oct | 35220046213411 |
9 | 7110754411684 |
10 | 2012202211081 |
11 | 706408765657 |
12 | 285b8a5481a1 |
13 | 11799957870a |
14 | 6d5692a798d |
15 | 3751e392821 |
hex | 1d480991709 |
2012202211081 has 2 divisors, whose sum is σ = 2012202211082. Its totient is φ = 2012202211080.
The previous prime is 2012202211037. The next prime is 2012202211109. The reversal of 2012202211081 is 1801122022102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1180230195456 + 831972015625 = 1086384^2 + 912125^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012202211081 - 219 = 2012201686793 is a prime.
It is a super-3 number, since 3×20122022110813 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (2012202211181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006101105540 + 1006101105541.
It is an arithmetic number, because the mean of its divisors is an integer number (1006101105541).
Almost surely, 22012202211081 is an apocalyptic number.
It is an amenable number.
2012202211081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012202211081 is an equidigital number, since it uses as much as digits as its factorization.
2012202211081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 256, while the sum is 22.
Adding to 2012202211081 its reverse (1801122022102), we get a palindrome (3813324233183).
The spelling of 2012202211081 in words is "two trillion, twelve billion, two hundred two million, two hundred eleven thousand, eighty-one".
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