Base | Representation |
---|---|
bin | 1001001001101000010101… |
… | …01000001111001111100001 |
3 | 2122020122122202100100122221 |
4 | 10210310022220033033201 |
5 | 10114140030111231423 |
6 | 110443544251031041 |
7 | 4144526253534652 |
oct | 444641250171741 |
9 | 78218582310587 |
10 | 20122100102113 |
11 | 6458809a1aa39 |
12 | 230b96a73b481 |
13 | b2c6765c3579 |
14 | 4d7cb4479529 |
15 | 24d64e3c3e5d |
hex | 124d0aa0f3e1 |
20122100102113 has 2 divisors, whose sum is σ = 20122100102114. Its totient is φ = 20122100102112.
The previous prime is 20122100102059. The next prime is 20122100102141. The reversal of 20122100102113 is 31120100122102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12024478622689 + 8097621479424 = 3467633^2 + 2845632^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20122100102113 is a prime.
It is not a weakly prime, because it can be changed into another prime (20122106102113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061050051056 + 10061050051057.
It is an arithmetic number, because the mean of its divisors is an integer number (10061050051057).
Almost surely, 220122100102113 is an apocalyptic number.
It is an amenable number.
20122100102113 is a deficient number, since it is larger than the sum of its proper divisors (1).
20122100102113 is an equidigital number, since it uses as much as digits as its factorization.
20122100102113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 20122100102113 its reverse (31120100122102), we get a palindrome (51242200224215).
The spelling of 20122100102113 in words is "twenty trillion, one hundred twenty-two billion, one hundred million, one hundred two thousand, one hundred thirteen".
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