Base | Representation |
---|---|
bin | 101101110000001001101100… |
… | …100111100010100100010011 |
3 | 222101110112200021001010010111 |
4 | 231300021230213202210103 |
5 | 202333301142232402011 |
6 | 1551543400352542151 |
7 | 60245511646152511 |
oct | 5560115447424423 |
9 | 871415607033114 |
10 | 201221040122131 |
11 | 5912a400366627 |
12 | 1a699b9b251957 |
13 | 88380a78989a3 |
14 | 37992166274b1 |
15 | 183e34aea0121 |
hex | b7026c9e2913 |
201221040122131 has 2 divisors, whose sum is σ = 201221040122132. Its totient is φ = 201221040122130.
The previous prime is 201221040122023. The next prime is 201221040122183. The reversal of 201221040122131 is 131221040122102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201221040122131 - 219 = 201221039597843 is a prime.
It is a super-2 number, since 2×2012210401221312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201221040122831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100610520061065 + 100610520061066.
It is an arithmetic number, because the mean of its divisors is an integer number (100610520061066).
Almost surely, 2201221040122131 is an apocalyptic number.
201221040122131 is a deficient number, since it is larger than the sum of its proper divisors (1).
201221040122131 is an equidigital number, since it uses as much as digits as its factorization.
201221040122131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 201221040122131 its reverse (131221040122102), we get a palindrome (332442080244233).
The spelling of 201221040122131 in words is "two hundred one trillion, two hundred twenty-one billion, forty million, one hundred twenty-two thousand, one hundred thirty-one".
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