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201221040122131 is a prime number
BaseRepresentation
bin101101110000001001101100…
…100111100010100100010011
3222101110112200021001010010111
4231300021230213202210103
5202333301142232402011
61551543400352542151
760245511646152511
oct5560115447424423
9871415607033114
10201221040122131
115912a400366627
121a699b9b251957
1388380a78989a3
1437992166274b1
15183e34aea0121
hexb7026c9e2913

201221040122131 has 2 divisors, whose sum is σ = 201221040122132. Its totient is φ = 201221040122130.

The previous prime is 201221040122023. The next prime is 201221040122183. The reversal of 201221040122131 is 131221040122102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 201221040122131 - 219 = 201221039597843 is a prime.

It is a super-2 number, since 2×2012210401221312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (201221040122831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100610520061065 + 100610520061066.

It is an arithmetic number, because the mean of its divisors is an integer number (100610520061066).

Almost surely, 2201221040122131 is an apocalyptic number.

201221040122131 is a deficient number, since it is larger than the sum of its proper divisors (1).

201221040122131 is an equidigital number, since it uses as much as digits as its factorization.

201221040122131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 201221040122131 its reverse (131221040122102), we get a palindrome (332442080244233).

The spelling of 201221040122131 in words is "two hundred one trillion, two hundred twenty-one billion, forty million, one hundred twenty-two thousand, one hundred thirty-one".