Base | Representation |
---|---|
bin | 1001001001101000010110… |
… | …10010100100101111001001 |
3 | 2122020122200112020012101020 |
4 | 10210310023102210233021 |
5 | 10114140040431401301 |
6 | 110443545324543053 |
7 | 4144526450056623 |
oct | 444641322445711 |
9 | 78218615205336 |
10 | 20122111200201 |
11 | 645881521010a |
12 | 230b9723b1a89 |
13 | b2c6789aab9a |
14 | 4d7cb5b27c13 |
15 | 24d650367436 |
hex | 124d0b4a4bc9 |
20122111200201 has 4 divisors (see below), whose sum is σ = 26829481600272. Its totient is φ = 13414740800132.
The previous prime is 20122111200197. The next prime is 20122111200251. The reversal of 20122111200201 is 10200211122102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20122111200201 - 22 = 20122111200197 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20122111200251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3353685200031 + ... + 3353685200036.
It is an arithmetic number, because the mean of its divisors is an integer number (6707370400068).
Almost surely, 220122111200201 is an apocalyptic number.
It is an amenable number.
20122111200201 is a deficient number, since it is larger than the sum of its proper divisors (6707370400071).
20122111200201 is an equidigital number, since it uses as much as digits as its factorization.
20122111200201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6707370400070.
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 20122111200201 its reverse (10200211122102), we get a palindrome (30322322322303).
The spelling of 20122111200201 in words is "twenty trillion, one hundred twenty-two billion, one hundred eleven million, two hundred thousand, two hundred one".
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