Base | Representation |
---|---|
bin | 1001001001101000100010… |
… | …10000001000000111111011 |
3 | 2122020122221111102211111201 |
4 | 10210310101100020013323 |
5 | 10114140242033101021 |
6 | 110444003300435031 |
7 | 4144532103202453 |
oct | 444642120100773 |
9 | 78218844384451 |
10 | 20122211222011 |
11 | 6458866716a68 |
12 | 230b99b9a8a77 |
13 | b2c69362b5a2 |
14 | 4d7cc5122d63 |
15 | 24d659023591 |
hex | 124d114081fb |
20122211222011 has 2 divisors, whose sum is σ = 20122211222012. Its totient is φ = 20122211222010.
The previous prime is 20122211221993. The next prime is 20122211222023. The reversal of 20122211222011 is 11022211222102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20122211222011 - 217 = 20122211090939 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20122211222011.
It is not a weakly prime, because it can be changed into another prime (20122211292011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061105611005 + 10061105611006.
It is an arithmetic number, because the mean of its divisors is an integer number (10061105611006).
Almost surely, 220122211222011 is an apocalyptic number.
20122211222011 is a deficient number, since it is larger than the sum of its proper divisors (1).
20122211222011 is an equidigital number, since it uses as much as digits as its factorization.
20122211222011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 20122211222011 its reverse (11022211222102), we get a palindrome (31144422444113).
Subtracting from 20122211222011 its reverse (11022211222102), we obtain a palindrome (9099999999909).
The spelling of 20122211222011 in words is "twenty trillion, one hundred twenty-two billion, two hundred eleven million, two hundred twenty-two thousand, eleven".
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