Base | Representation |
---|---|
bin | 11101010010000001110… |
… | …010001110010011111011 |
3 | 21010100220012220221100001 |
4 | 131102001302032103323 |
5 | 230432012330334321 |
6 | 4140222503253431 |
7 | 265243511551351 |
oct | 35220162162373 |
9 | 7110805827301 |
10 | 2012222121211 |
11 | 706418a24405 |
12 | 285b9514a277 |
13 | 1179a0729c63 |
14 | 6d56bbab7d1 |
15 | 37520ec6c91 |
hex | 1d481c8e4fb |
2012222121211 has 4 divisors (see below), whose sum is σ = 2017001746624. Its totient is φ = 2007442495800.
The previous prime is 2012222121191. The next prime is 2012222121257. The reversal of 2012222121211 is 1121212222102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2012222121211 - 225 = 2012188566779 is a prime.
It is a super-2 number, since 2×20122221212112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2012222121011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2389812075 + ... + 2389812916.
It is an arithmetic number, because the mean of its divisors is an integer number (504250436656).
Almost surely, 22012222121211 is an apocalyptic number.
2012222121211 is a deficient number, since it is larger than the sum of its proper divisors (4779625413).
2012222121211 is an equidigital number, since it uses as much as digits as its factorization.
2012222121211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4779625412.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 2012222121211 its reverse (1121212222102), we get a palindrome (3133434343313).
The spelling of 2012222121211 in words is "two trillion, twelve billion, two hundred twenty-two million, one hundred twenty-one thousand, two hundred eleven".
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