Search a number
-
+
20123004115 = 531671937699
BaseRepresentation
bin10010101111011011…
…001010110011010011
31220221101222112011201
4102233123022303103
5312202442112430
613124441452031
71311444466324
oct225733126323
956841875151
1020123004115
118596a02915
123a971a1017
131b89014036
14d8c78444b
157cb9668ca
hex4af6cacd3

20123004115 has 16 divisors (see below), whose sum is σ = 25298611200. Its totient is φ = 15346568160.

The previous prime is 20123004029. The next prime is 20123004151. The reversal of 20123004115 is 51140032102.

It is not a de Polignac number, because 20123004115 - 213 = 20122995923 is a prime.

It is a super-2 number, since 2×201230041152 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20123004092 and 20123004101.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 958465 + ... + 979234.

It is an arithmetic number, because the mean of its divisors is an integer number (1581163200).

Almost surely, 220123004115 is an apocalyptic number.

20123004115 is a deficient number, since it is larger than the sum of its proper divisors (5175607085).

20123004115 is a wasteful number, since it uses less digits than its factorization.

20123004115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1937802.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 20123004115 its reverse (51140032102), we get a palindrome (71263036217).

It can be divided in two parts, 201230041 and 15, that added together give a cube (201230056 = 5863).

The spelling of 20123004115 in words is "twenty billion, one hundred twenty-three million, four thousand, one hundred fifteen".

Divisors: 1 5 31 67 155 335 2077 10385 1937699 9688495 60068669 129825833 300343345 649129165 4024600823 20123004115