Base | Representation |
---|---|
bin | 1001001001101010110011… |
… | …00011000000100011111011 |
3 | 2122020210002000202000021211 |
4 | 10210311121203000203323 |
5 | 10114200233034200243 |
6 | 110444323505343551 |
7 | 4144604131565302 |
oct | 444653143004373 |
9 | 78223060660254 |
10 | 20123424131323 |
11 | 645932933a757 |
12 | 231007a037bb7 |
13 | b2c8279c28c6 |
14 | 4d7d9c253439 |
15 | 24d6ca75dd9d |
hex | 124d598c08fb |
20123424131323 has 2 divisors, whose sum is σ = 20123424131324. Its totient is φ = 20123424131322.
The previous prime is 20123424131311. The next prime is 20123424131341. The reversal of 20123424131323 is 32313142432102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20123424131323 is a prime.
It is a super-2 number, since 2×201234241313232 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20123424131353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061712065661 + 10061712065662.
It is an arithmetic number, because the mean of its divisors is an integer number (10061712065662).
Almost surely, 220123424131323 is an apocalyptic number.
20123424131323 is a deficient number, since it is larger than the sum of its proper divisors (1).
20123424131323 is an equidigital number, since it uses as much as digits as its factorization.
20123424131323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 20123424131323 its reverse (32313142432102), we get a palindrome (52436566563425).
The spelling of 20123424131323 in words is "twenty trillion, one hundred twenty-three billion, four hundred twenty-four million, one hundred thirty-one thousand, three hundred twenty-three".
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