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20124111303434 = 2142759231190477
BaseRepresentation
bin1001001001101100000101…
…00000010111001100001010
32122020211211220202222012202
410210312002200113030022
510114203134443202214
6110444520014040202
74144630144501445
oct444660240271412
978224756688182
1020124111303434
116459651218296
1223102301a9062
13b2c907190218
144d802560c65c
1524d71ac4a6de
hex124d8281730a

20124111303434 has 16 divisors (see below), whose sum is σ = 30212445922848. Its totient is φ = 10053298391472.

The previous prime is 20124111303433. The next prime is 20124111303493. The reversal of 20124111303434 is 43430311142102.

It is a junction number, because it is equal to n+sod(n) for n = 20124111303397 and 20124111303406.

It is not an unprimeable number, because it can be changed into a prime (20124111303433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16309004 + ... + 17499480.

It is an arithmetic number, because the mean of its divisors is an integer number (1888277870178).

Almost surely, 220124111303434 is an apocalyptic number.

20124111303434 is a deficient number, since it is larger than the sum of its proper divisors (10088334619414).

20124111303434 is a wasteful number, since it uses less digits than its factorization.

20124111303434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1197829.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 20124111303434 its reverse (43430311142102), we get a palindrome (63554422445536).

The spelling of 20124111303434 in words is "twenty trillion, one hundred twenty-four billion, one hundred eleven million, three hundred three thousand, four hundred thirty-four".

Divisors: 1 2 1427 2854 5923 11846 1190477 2380954 8452121 16904242 1698810679 3397621358 7051195271 14102390542 10062055651717 20124111303434