Base | Representation |
---|---|
bin | 11101010010110000010… |
… | …101111000100010000011 |
3 | 21010102220122200220222102 |
4 | 131102300111320202003 |
5 | 230440112311033443 |
6 | 4140432205101015 |
7 | 265302045026516 |
oct | 35226025704203 |
9 | 7112818626872 |
10 | 2013003221123 |
11 | 706789926324 |
12 | 28617285776b |
13 | 117a964c325b |
14 | 6d603816d7d |
15 | 37569868cb8 |
hex | 1d4b0578883 |
2013003221123 has 2 divisors, whose sum is σ = 2013003221124. Its totient is φ = 2013003221122.
The previous prime is 2013003221113. The next prime is 2013003221147. The reversal of 2013003221123 is 3211223003102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013003221123 - 26 = 2013003221059 is a prime.
It is a super-2 number, since 2×20130032211232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2013003221095 and 2013003221104.
It is not a weakly prime, because it can be changed into another prime (2013003221113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006501610561 + 1006501610562.
It is an arithmetic number, because the mean of its divisors is an integer number (1006501610562).
Almost surely, 22013003221123 is an apocalyptic number.
2013003221123 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013003221123 is an equidigital number, since it uses as much as digits as its factorization.
2013003221123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2013003221123 its reverse (3211223003102), we get a palindrome (5224226224225).
The spelling of 2013003221123 in words is "two trillion, thirteen billion, three million, two hundred twenty-one thousand, one hundred twenty-three".
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