Base | Representation |
---|---|
bin | 1001001001110111001000… |
… | …01001000000110111011011 |
3 | 2122021102011101210021222101 |
4 | 10210323210021000313123 |
5 | 10114302312321122042 |
6 | 110451340435104231 |
7 | 4145230156334512 |
oct | 444734411006733 |
9 | 78242141707871 |
10 | 20130044317147 |
11 | 6461116256306 |
12 | 2311407142077 |
13 | b3034140411b |
14 | 4d8429581679 |
15 | 24d966a506b7 |
hex | 124ee4240ddb |
20130044317147 has 2 divisors, whose sum is σ = 20130044317148. Its totient is φ = 20130044317146.
The previous prime is 20130044317127. The next prime is 20130044317157. The reversal of 20130044317147 is 74171344003102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20130044317147 - 223 = 20130035928539 is a prime.
It is not a weakly prime, because it can be changed into another prime (20130044317127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065022158573 + 10065022158574.
It is an arithmetic number, because the mean of its divisors is an integer number (10065022158574).
Almost surely, 220130044317147 is an apocalyptic number.
20130044317147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130044317147 is an equidigital number, since it uses as much as digits as its factorization.
20130044317147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56448, while the sum is 37.
The spelling of 20130044317147 in words is "twenty trillion, one hundred thirty billion, forty-four million, three hundred seventeen thousand, one hundred forty-seven".
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