Base | Representation |
---|---|
bin | 101101110001010100001100… |
… | …100000011011010000110001 |
3 | 222101202012011000220201022221 |
4 | 231301110030200123100301 |
5 | 202341104003144214324 |
6 | 1552044230101001041 |
7 | 60254343142122655 |
oct | 5561241440332061 |
9 | 871665130821287 |
10 | 201301032023089 |
11 | 59160319740789 |
12 | 1a6b15a43b3181 |
13 | 88427b512626b |
14 | 379d044294a65 |
15 | 184147d8be0e4 |
hex | b7150c81b431 |
201301032023089 has 2 divisors, whose sum is σ = 201301032023090. Its totient is φ = 201301032023088.
The previous prime is 201301032023017. The next prime is 201301032023131. The reversal of 201301032023089 is 980320230103102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 176660649390625 + 24640382632464 = 13291375^2 + 4963908^2 .
It is a cyclic number.
It is not a de Polignac number, because 201301032023089 - 215 = 201301031990321 is a prime.
It is not a weakly prime, because it can be changed into another prime (201301032023009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100650516011544 + 100650516011545.
It is an arithmetic number, because the mean of its divisors is an integer number (100650516011545).
Almost surely, 2201301032023089 is an apocalyptic number.
It is an amenable number.
201301032023089 is a deficient number, since it is larger than the sum of its proper divisors (1).
201301032023089 is an equidigital number, since it uses as much as digits as its factorization.
201301032023089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 201301032023089 in words is "two hundred one trillion, three hundred one billion, thirty-two million, twenty-three thousand, eighty-nine".
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