Base | Representation |
---|---|
bin | 11101010010110000110… |
… | …011100011101011011111 |
3 | 21010102221012100010122010 |
4 | 131102300303203223133 |
5 | 230440121304000111 |
6 | 4140433043522303 |
7 | 265302201115533 |
oct | 35226063435337 |
9 | 7112835303563 |
10 | 2013011000031 |
11 | 706793259779 |
12 | 286175389393 |
13 | 117a97cb7b65 |
14 | 6d60487dbc3 |
15 | 3756a3a3aa6 |
hex | 1d4b0ce3adf |
2013011000031 has 16 divisors (see below), whose sum is σ = 2729604337920. Its totient is φ = 1319214129600.
The previous prime is 2013011000027. The next prime is 2013011000053. The reversal of 2013011000031 is 1300001103102.
It is not a de Polignac number, because 2013011000031 - 22 = 2013011000027 is a prime.
It is a super-2 number, since 2×20130110000312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2013010999980 and 2013011000016.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013011000431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5139331 + ... + 5517131.
It is an arithmetic number, because the mean of its divisors is an integer number (170600271120).
Almost surely, 22013011000031 is an apocalyptic number.
2013011000031 is a deficient number, since it is larger than the sum of its proper divisors (716593337889).
2013011000031 is a wasteful number, since it uses less digits than its factorization.
2013011000031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 407966.
The product of its (nonzero) digits is 18, while the sum is 12.
Adding to 2013011000031 its reverse (1300001103102), we get a palindrome (3313012103133).
The spelling of 2013011000031 in words is "two trillion, thirteen billion, eleven million, thirty-one", and thus it is an aban number and an uban number.
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