Base | Representation |
---|---|
bin | 11101010010110000110… |
… | …100010101000100010011 |
3 | 21010102221012201102010102 |
4 | 131102300310111010103 |
5 | 230440121331433243 |
6 | 4140433052123015 |
7 | 265302202620362 |
oct | 35226064250423 |
9 | 7112835642112 |
10 | 2013011202323 |
11 | 706793387760 |
12 | 28617546646b |
13 | 117a98058c64 |
14 | 6d6048d37d9 |
15 | 3756a3e39b8 |
hex | 1d4b0d15113 |
2013011202323 has 32 divisors (see below), whose sum is σ = 2368489697280. Its totient is φ = 1691038944000.
The previous prime is 2013011202317. The next prime is 2013011202431. The reversal of 2013011202323 is 3232021103102.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013011202323 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2013011202295 and 2013011202304.
It is not an unprimeable number, because it can be changed into a prime (2013011202313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 43481678 + ... + 43527948.
It is an arithmetic number, because the mean of its divisors is an integer number (74015303040).
Almost surely, 22013011202323 is an apocalyptic number.
2013011202323 is a deficient number, since it is larger than the sum of its proper divisors (355478494957).
2013011202323 is a wasteful number, since it uses less digits than its factorization.
2013011202323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51419.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2013011202323 its reverse (3232021103102), we get a palindrome (5245032305425).
The spelling of 2013011202323 in words is "two trillion, thirteen billion, eleven million, two hundred two thousand, three hundred twenty-three".
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