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201301201217 is a prime number
BaseRepresentation
bin1011101101111001111…
…1001001000101000001
3201020121000201120000002
42323132133021011001
511244231101414332
6232250531205345
720354300656364
oct2733637110501
9636530646002
10201301201217
117840a309a06
123301b446855
1315ca0a87b1c
149a58c360db
155382800562
hex2ede7c9141

201301201217 has 2 divisors, whose sum is σ = 201301201218. Its totient is φ = 201301201216.

The previous prime is 201301201201. The next prime is 201301201223. The reversal of 201301201217 is 712102103102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122833426576 + 78467774641 = 350476^2 + 280121^2 .

It is a cyclic number.

It is not a de Polignac number, because 201301201217 - 24 = 201301201201 is a prime.

It is a super-2 number, since 2×2013012012172 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (201300201217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100650600608 + 100650600609.

It is an arithmetic number, because the mean of its divisors is an integer number (100650600609).

Almost surely, 2201301201217 is an apocalyptic number.

It is an amenable number.

201301201217 is a deficient number, since it is larger than the sum of its proper divisors (1).

201301201217 is an equidigital number, since it uses as much as digits as its factorization.

201301201217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 20.

Adding to 201301201217 its reverse (712102103102), we get a palindrome (913403304319).

The spelling of 201301201217 in words is "two hundred one billion, three hundred one million, two hundred one thousand, two hundred seventeen".