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20130121111330 = 253526757079199
BaseRepresentation
bin1001001001110111010001…
…01101111101011100100010
32122021102100202021211210101
410210323220231331130202
510114302442001030310
6110451352221053014
74145232111146326
oct444735055753442
978242322254711
1020130121111330
11646115563797a
1223114289b716a
13b303542b1279
144d8435851986
1524d96d66e43a
hex124ee8b7d722

20130121111330 has 16 divisors (see below), whose sum is σ = 36235246060800. Its totient is φ = 8051819986672.

The previous prime is 20130121111327. The next prime is 20130121111333. The reversal of 20130121111330 is 3311112103102.

It is an interprime number because it is at equal distance from previous prime (20130121111327) and next prime (20130121111333).

It is a junction number, because it is equal to n+sod(n) for n = 20130121111298 and 20130121111307.

It is not an unprimeable number, because it can be changed into a prime (20130121111333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28186930 + ... + 28892269.

It is an arithmetic number, because the mean of its divisors is an integer number (2264702878800).

Almost surely, 220130121111330 is an apocalyptic number.

20130121111330 is a deficient number, since it is larger than the sum of its proper divisors (16105124949470).

20130121111330 is a wasteful number, since it uses less digits than its factorization.

20130121111330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57114473.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 20130121111330 its reverse (3311112103102), we get a palindrome (23441233214432).

The spelling of 20130121111330 in words is "twenty trillion, one hundred thirty billion, one hundred twenty-one million, one hundred eleven thousand, three hundred thirty".

Divisors: 1 2 5 10 35267 70534 176335 352670 57079199 114158398 285395995 570791990 2013012111133 4026024222266 10065060555665 20130121111330