Base | Representation |
---|---|
bin | 11101010010110000111… |
… | …011101100011111000001 |
3 | 21010102221100100111212012 |
4 | 131102300323230133001 |
5 | 230440122330230444 |
6 | 4140433201342305 |
7 | 265302225212036 |
oct | 35226073543701 |
9 | 7112840314765 |
10 | 2013013133249 |
11 | 706794486468 |
12 | 286176037995 |
13 | 117a98583b11 |
14 | 6d604c7738d |
15 | 3756a675b9e |
hex | 1d4b0eec7c1 |
2013013133249 has 2 divisors, whose sum is σ = 2013013133250. Its totient is φ = 2013013133248.
The previous prime is 2013013133231. The next prime is 2013013133311. The reversal of 2013013133249 is 9423313103102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1974497108224 + 38516025025 = 1405168^2 + 196255^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013013133249 - 216 = 2013013067713 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013013103249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006506566624 + 1006506566625.
It is an arithmetic number, because the mean of its divisors is an integer number (1006506566625).
Almost surely, 22013013133249 is an apocalyptic number.
It is an amenable number.
2013013133249 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013013133249 is an equidigital number, since it uses as much as digits as its factorization.
2013013133249 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 32.
The spelling of 2013013133249 in words is "two trillion, thirteen billion, thirteen million, one hundred thirty-three thousand, two hundred forty-nine".
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