Base | Representation |
---|---|
bin | 10010101111110110… |
… | …100111101101111011 |
3 | 1220221220112010200101 |
4 | 102233312213231323 |
5 | 312211312403233 |
6 | 13125300020231 |
7 | 1311562611013 |
oct | 225766475573 |
9 | 56856463611 |
10 | 20130200443 |
11 | 859aa785a1 |
12 | 3a99691677 |
13 | 1b8a663712 |
14 | d8d6d8c43 |
15 | 7cc3d8c7d |
hex | 4afda7b7b |
20130200443 has 2 divisors, whose sum is σ = 20130200444. Its totient is φ = 20130200442.
The previous prime is 20130200423. The next prime is 20130200449. The reversal of 20130200443 is 34400203102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20130200443 - 29 = 20130199931 is a prime.
It is a super-3 number, since 3×201302004433 (a number of 32 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 20130200443.
It is not a weakly prime, because it can be changed into another prime (20130200449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065100221 + 10065100222.
It is an arithmetic number, because the mean of its divisors is an integer number (10065100222).
Almost surely, 220130200443 is an apocalyptic number.
20130200443 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130200443 is an equidigital number, since it uses as much as digits as its factorization.
20130200443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 19.
Adding to 20130200443 its reverse (34400203102), we get a palindrome (54530403545).
The spelling of 20130200443 in words is "twenty billion, one hundred thirty million, two hundred thousand, four hundred forty-three".
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