Search a number
-
+
20130204004 = 225032551001
BaseRepresentation
bin10010101111110110…
…101000100101100100
31220221220112022120021
4102233312220211210
5312211313012004
613125300044524
71311562624261
oct225766504544
956856468507
1020130204004
11859aa80239
123a99693744
131b8a665221
14d8d6da268
157cc3d9d54
hex4afda8964

20130204004 has 6 divisors (see below), whose sum is σ = 35227857014. Its totient is φ = 10065102000.

The previous prime is 20130204001. The next prime is 20130204007. The reversal of 20130204004 is 40040203102.

It is an interprime number because it is at equal distance from previous prime (20130204001) and next prime (20130204007).

It can be written as a sum of positive squares in only one way, i.e., 10588821604 + 9541382400 = 102902^2 + 97680^2 .

It is a super-2 number, since 2×201302040042 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (20130204001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516275497 + ... + 2516275504.

Almost surely, 220130204004 is an apocalyptic number.

It is an amenable number.

20130204004 is a deficient number, since it is larger than the sum of its proper divisors (15097653010).

20130204004 is a wasteful number, since it uses less digits than its factorization.

20130204004 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5032551005 (or 5032551003 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 16.

Adding to 20130204004 its reverse (40040203102), we get a palindrome (60170407106).

The spelling of 20130204004 in words is "twenty billion, one hundred thirty million, two hundred four thousand, four".

Divisors: 1 2 4 5032551001 10065102002 20130204004