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20130212203 = 140331434491
BaseRepresentation
bin10010101111110110…
…101010100101101011
31220221220112201210221
4102233312222211223
5312211313242303
613125300150511
71311562660213
oct225766524553
956856481727
1020130212203
11859aa86412
123a99698437
131b8a668b8a
14d8d6dd243
157cc3dc4bd
hex4afdaa96b

20130212203 has 4 divisors (see below), whose sum is σ = 20131660728. Its totient is φ = 20128763680.

The previous prime is 20130212161. The next prime is 20130212213. The reversal of 20130212203 is 30221203102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20130212203 - 29 = 20130211691 is a prime.

It is a super-3 number, since 3×201302122033 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20130212213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 703213 + ... + 731278.

It is an arithmetic number, because the mean of its divisors is an integer number (5032915182).

Almost surely, 220130212203 is an apocalyptic number.

20130212203 is a deficient number, since it is larger than the sum of its proper divisors (1448525).

20130212203 is a wasteful number, since it uses less digits than its factorization.

20130212203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1448524.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 20130212203 its reverse (30221203102), we get a palindrome (50351415305).

The spelling of 20130212203 in words is "twenty billion, one hundred thirty million, two hundred twelve thousand, two hundred three".

Divisors: 1 14033 1434491 20130212203