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201302322300043 is a prime number
BaseRepresentation
bin101101110001010101011001…
…011010011100010010001011
3222101202022110221210120120021
4231301111121122130102023
5202341114124002100133
61552045002112041311
760254420130236236
oct5561253132342213
9871668427716507
10201302322300043
1159160920aa7978
121a6b18a4533237
13884295c538753
14379d1277a441d
151841506cdd52d
hexb7155969c48b

201302322300043 has 2 divisors, whose sum is σ = 201302322300044. Its totient is φ = 201302322300042.

The previous prime is 201302322299983. The next prime is 201302322300071. The reversal of 201302322300043 is 340003223203102.

201302322300043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201302322300043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201302322299990 and 201302322300017.

It is not a weakly prime, because it can be changed into another prime (201302322301043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100651161150021 + 100651161150022.

It is an arithmetic number, because the mean of its divisors is an integer number (100651161150022).

Almost surely, 2201302322300043 is an apocalyptic number.

201302322300043 is a deficient number, since it is larger than the sum of its proper divisors (1).

201302322300043 is an equidigital number, since it uses as much as digits as its factorization.

201302322300043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 201302322300043 its reverse (340003223203102), we get a palindrome (541305545503145).

The spelling of 201302322300043 in words is "two hundred one trillion, three hundred two billion, three hundred twenty-two million, three hundred thousand, forty-three".