Base | Representation |
---|---|
bin | 1001001001110111011110… |
… | …11010000101010010111011 |
3 | 2122021102122120110201010002 |
4 | 10210323233122011102323 |
5 | 10114303204213403430 |
6 | 110451411310343215 |
7 | 4145234643116012 |
oct | 444735732052273 |
9 | 78242576421102 |
10 | 20130233341115 |
11 | 6461202a21867 |
12 | 231145a4bab0b |
13 | b30371617521 |
14 | 4d8446707a79 |
15 | 24d97843c845 |
hex | 124eef6854bb |
20130233341115 has 32 divisors (see below), whose sum is σ = 24710351339520. Its totient is φ = 15735940326144.
The previous prime is 20130233341063. The next prime is 20130233341117. The reversal of 20130233341115 is 51114333203102.
It is a cyclic number.
It is not a de Polignac number, because 20130233341115 - 244 = 2538047296699 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20130233341117) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 380370626 + ... + 380423544.
It is an arithmetic number, because the mean of its divisors is an integer number (772198479360).
Almost surely, 220130233341115 is an apocalyptic number.
20130233341115 is a deficient number, since it is larger than the sum of its proper divisors (4580117998405).
20130233341115 is a wasteful number, since it uses less digits than its factorization.
20130233341115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55571.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 20130233341115 its reverse (51114333203102), we get a palindrome (71244566544217).
The spelling of 20130233341115 in words is "twenty trillion, one hundred thirty billion, two hundred thirty-three million, three hundred forty-one thousand, one hundred fifteen".
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