Base | Representation |
---|---|
bin | 1001001001110111011110… |
… | …11010010011111010101001 |
3 | 2122021102122120120202021002 |
4 | 10210323233122103322221 |
5 | 10114303204222313001 |
6 | 110451411311524345 |
7 | 4145234643455423 |
oct | 444735732237251 |
9 | 78242576522232 |
10 | 20130233401001 |
11 | 6461202a62859 |
12 | 231145a5296b5 |
13 | b30371638869 |
14 | 4d8446721813 |
15 | 24d97845046b |
hex | 124eef693ea9 |
20130233401001 has 2 divisors, whose sum is σ = 20130233401002. Its totient is φ = 20130233401000.
The previous prime is 20130233400941. The next prime is 20130233401039. The reversal of 20130233401001 is 10010433203102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15190389325225 + 4939844075776 = 3897485^2 + 2222576^2 .
It is a cyclic number.
It is not a de Polignac number, because 20130233401001 - 210 = 20130233399977 is a prime.
It is not a weakly prime, because it can be changed into another prime (20130233401051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065116700500 + 10065116700501.
It is an arithmetic number, because the mean of its divisors is an integer number (10065116700501).
Almost surely, 220130233401001 is an apocalyptic number.
It is an amenable number.
20130233401001 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130233401001 is an equidigital number, since it uses as much as digits as its factorization.
20130233401001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 20130233401001 its reverse (10010433203102), we get a palindrome (30140666604103).
The spelling of 20130233401001 in words is "twenty trillion, one hundred thirty billion, two hundred thirty-three million, four hundred one thousand, one".
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