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2013024003 = 3671008001
BaseRepresentation
bin111011111111100…
…0100111100000011
312012021212012210120
41313333010330003
513110313232003
6531430031323
7100612264434
oct16777047403
95167765716
102013024003
11943332801
124821a8543
13261087483
141514c948b
15bbad6853
hex77fc4f03

2013024003 has 4 divisors (see below), whose sum is σ = 2684032008. Its totient is φ = 1342016000.

The previous prime is 2013024001. The next prime is 2013024019. The reversal of 2013024003 is 3004203102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013024003 - 21 = 2013024001 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2013024001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335503998 + ... + 335504003.

It is an arithmetic number, because the mean of its divisors is an integer number (671008002).

Almost surely, 22013024003 is an apocalyptic number.

2013024003 is a deficient number, since it is larger than the sum of its proper divisors (671008005).

2013024003 is an equidigital number, since it uses as much as digits as its factorization.

2013024003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 671008004.

The product of its (nonzero) digits is 144, while the sum is 15.

The square root of 2013024003 is about 44866.7360413035. The cubic root of 2013024003 is about 1262.6500040437.

Adding to 2013024003 its reverse (3004203102), we get a palindrome (5017227105).

The spelling of 2013024003 in words is "two billion, thirteen million, twenty-four thousand, three".

Divisors: 1 3 671008001 2013024003