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20130304143403 = 28796992116757
BaseRepresentation
bin1001001001110111100111…
…01000001011000000101011
32122021102211111200211121001
410210323303220023000223
510114303330330042103
6110451422320055431
74145236462663456
oct444736350130053
978242744624531
1020130304143403
116461239990653
12231147a164577
13b303831a727c
144d8451c9849d
1524d97e77601d
hex124ef3a0b02b

20130304143403 has 4 divisors (see below), whose sum is σ = 20137296263040. Its totient is φ = 20123312023768.

The previous prime is 20130304143337. The next prime is 20130304143427. The reversal of 20130304143403 is 30434140303102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20130304143403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20130304143473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3496055500 + ... + 3496061257.

It is an arithmetic number, because the mean of its divisors is an integer number (5034324065760).

Almost surely, 220130304143403 is an apocalyptic number.

20130304143403 is a deficient number, since it is larger than the sum of its proper divisors (6992119637).

20130304143403 is an equidigital number, since it uses as much as digits as its factorization.

20130304143403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6992119636.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 20130304143403 its reverse (30434140303102), we get a palindrome (50564444446505).

The spelling of 20130304143403 in words is "twenty trillion, one hundred thirty billion, three hundred four million, one hundred forty-three thousand, four hundred three".

Divisors: 1 2879 6992116757 20130304143403