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201303113132081 is a prime number
BaseRepresentation
bin101101110001010110001000…
…100011001110100000110001
3222101202101112001220000011202
4231301112020203032200301
5202341122233430211311
61552045212402220545
760254445542220062
oct5561261043164061
9871671461800152
10201303113132081
1159161197446774
121a6b1a85354755
138842a5732b6bc
14379d1a0824569
151841551453e3b
hexb715888ce831

201303113132081 has 2 divisors, whose sum is σ = 201303113132082. Its totient is φ = 201303113132080.

The previous prime is 201303113132029. The next prime is 201303113132167. The reversal of 201303113132081 is 180231311303102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 186068259987856 + 15234853144225 = 13640684^2 + 3903185^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201303113132081 is a prime.

It is a super-2 number, since 2×2013031131320812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (201303113102081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100651556566040 + 100651556566041.

It is an arithmetic number, because the mean of its divisors is an integer number (100651556566041).

Almost surely, 2201303113132081 is an apocalyptic number.

It is an amenable number.

201303113132081 is a deficient number, since it is larger than the sum of its proper divisors (1).

201303113132081 is an equidigital number, since it uses as much as digits as its factorization.

201303113132081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

Adding to 201303113132081 its reverse (180231311303102), we get a palindrome (381534424435183).

The spelling of 201303113132081 in words is "two hundred one trillion, three hundred three billion, one hundred thirteen million, one hundred thirty-two thousand, eighty-one".