Base | Representation |
---|---|
bin | 11101010010110010000… |
… | …001001100111100100001 |
3 | 21010102222121122020020012 |
4 | 131102302001030330201 |
5 | 230440142011313040 |
6 | 4140435052054305 |
7 | 265302536121140 |
oct | 35226201147441 |
9 | 7112877566205 |
10 | 2013031354145 |
11 | 7067a37a1059 |
12 | 286180164395 |
13 | 117a9c293506 |
14 | 6d60745b757 |
15 | 3756c074865 |
hex | 1d4b204cf21 |
2013031354145 has 16 divisors (see below), whose sum is σ = 2849784480768. Its totient is φ = 1335836473920.
The previous prime is 2013031354123. The next prime is 2013031354157. The reversal of 2013031354145 is 5414531303102.
It is not a de Polignac number, because 2013031354145 - 210 = 2013031353121 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 927663134 + ... + 927665303.
It is an arithmetic number, because the mean of its divisors is an integer number (178111530048).
Almost surely, 22013031354145 is an apocalyptic number.
It is an amenable number.
2013031354145 is a deficient number, since it is larger than the sum of its proper divisors (836753126623).
2013031354145 is a wasteful number, since it uses less digits than its factorization.
2013031354145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1855328480.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 2013031354145 its reverse (5414531303102), we get a palindrome (7427562657247).
The spelling of 2013031354145 in words is "two trillion, thirteen billion, thirty-one million, three hundred fifty-four thousand, one hundred forty-five".
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