Base | Representation |
---|---|
bin | 11101010010110010100… |
… | …010101010011110111111 |
3 | 21010110000020010212210112 |
4 | 131102302202222132333 |
5 | 230440201233012022 |
6 | 4140440004100235 |
7 | 265303003513550 |
oct | 35226242523677 |
9 | 7113006125715 |
10 | 2013040125887 |
11 | 7067a874242a |
12 | 28618309467b |
13 | 117aa1044cab |
14 | 6d6086a2327 |
15 | 3756cc088e2 |
hex | 1d4b28aa7bf |
2013040125887 has 16 divisors (see below), whose sum is σ = 2310376504320. Its totient is φ = 1718144387232.
The previous prime is 2013040125881. The next prime is 2013040125923. The reversal of 2013040125887 is 7885210403102.
It is not a de Polignac number, because 2013040125887 - 26 = 2013040125823 is a prime.
It is a super-2 number, since 2×20130401258872 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013040125881) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 57890168 + ... + 57924930.
It is an arithmetic number, because the mean of its divisors is an integer number (144398531520).
Almost surely, 22013040125887 is an apocalyptic number.
2013040125887 is a deficient number, since it is larger than the sum of its proper divisors (297336378433).
2013040125887 is a wasteful number, since it uses less digits than its factorization.
2013040125887 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69622.
The product of its (nonzero) digits is 107520, while the sum is 41.
Adding to 2013040125887 its reverse (7885210403102), we get a palindrome (9898250528989).
The spelling of 2013040125887 in words is "two trillion, thirteen billion, forty million, one hundred twenty-five thousand, eight hundred eighty-seven".
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