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20130424120003 = 145611382489123
BaseRepresentation
bin1001001001110111110101…
…10001110110001011000011
32122021110010212110021112211
410210323322301312023003
510114304102033320003
6110451442243402551
74145242450526461
oct444737261661303
978243125407484
1020130424120003
1164612a068686a
1223114b2383457
13b303a1cc3642
144d8463ba9831
1524d98a07496d
hex124efac762c3

20130424120003 has 4 divisors (see below), whose sum is σ = 20131806623688. Its totient is φ = 20129041616320.

The previous prime is 20130424119997. The next prime is 20130424120043. The reversal of 20130424120003 is 30002142403102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20130424120003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20130424120043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 691230001 + ... + 691259122.

It is an arithmetic number, because the mean of its divisors is an integer number (5032951655922).

Almost surely, 220130424120003 is an apocalyptic number.

20130424120003 is a deficient number, since it is larger than the sum of its proper divisors (1382503685).

20130424120003 is a wasteful number, since it uses less digits than its factorization.

20130424120003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1382503684.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 20130424120003 its reverse (30002142403102), we get a palindrome (50132566523105).

The spelling of 20130424120003 in words is "twenty trillion, one hundred thirty billion, four hundred twenty-four million, one hundred twenty thousand, three".

Divisors: 1 14561 1382489123 20130424120003