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2013044203121 = 72919750337431
BaseRepresentation
bin11101010010110010110…
…010001101111001110001
321010110000111211000201012
4131102302302031321301
5230440203303444441
64140440231320305
7265303053254540
oct35226262157161
97113014730635
102013044203121
117067aaa77746
12286184520095
13117aa1b41a63
146d609044157
153756d2619eb
hex1d4b2c8de71

2013044203121 has 16 divisors (see below), whose sum is σ = 2392034768640. Its totient is φ = 1657510895040.

The previous prime is 2013044203117. The next prime is 2013044203133. The reversal of 2013044203121 is 1213024403102.

It is not a de Polignac number, because 2013044203121 - 22 = 2013044203117 is a prime.

It is a super-2 number, since 2×20130442031212 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013044203171) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25128725 + ... + 25208706.

It is an arithmetic number, because the mean of its divisors is an integer number (149502173040).

Almost surely, 22013044203121 is an apocalyptic number.

It is an amenable number.

2013044203121 is a deficient number, since it is larger than the sum of its proper divisors (378990565519).

2013044203121 is a wasteful number, since it uses less digits than its factorization.

2013044203121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50337664.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 2013044203121 its reverse (1213024403102), we get a palindrome (3226068606223).

The spelling of 2013044203121 in words is "two trillion, thirteen billion, forty-four million, two hundred three thousand, one hundred twenty-one".

Divisors: 1 7 29 197 203 1379 5713 39991 50337431 352362017 1459785499 9916473907 10218498493 69415317349 287577743303 2013044203121