2013101123041 has 4 divisors (see below), whose sum is σ = 2059917428272. Its totient is φ = 1966284817812.

The previous prime is 2013101122943. The next prime is 2013101123123. The reversal of 2013101123041 is 1403211013102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2013101123041 - 2³¹ = 2010953639393 is a prime.

It is a super-2 number, since 2×2013101123041² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013101121041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23408152551 + ... + 23408152636.

It is an arithmetic number, because the mean of its divisors is an integer number (514979357068).

Almost surely, 2^{2013101123041} is an apocalyptic number.

It is an amenable number.

2013101123041 is a deficient number, since it is larger than the sum of its proper divisors (46816305231).

2013101123041 is an equidigital number, since it uses as much as digits as its factorization.

2013101123041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46816305230.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2013101123041 its reverse (1403211013102), we get a palindrome (3416312136143).

The spelling of 2013101123041 in words is "two trillion, thirteen billion, one hundred one million, one hundred twenty-three thousand, forty-one".