Base | Representation |
---|---|
bin | 1011101101111100010… |
… | …0111010010001000110 |
3 | 201020121201100120100120 |
4 | 2323133010322101012 |
5 | 11244241120231042 |
6 | 232251523322410 |
7 | 20354451063612 |
oct | 2733704722106 |
9 | 636551316316 |
10 | 201311102022 |
11 | 78414961598 |
12 | 33022820406 |
13 | 15ca2b434a4 |
14 | 9a5a292342 |
15 | 5383608dec |
hex | 2edf13a446 |
201311102022 has 32 divisors (see below), whose sum is σ = 404876659200. Its totient is φ = 66728344320.
The previous prime is 201311102011. The next prime is 201311102023. The reversal of 201311102022 is 220201113102.
201311102022 is digitally balanced in base 7, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 201311101992 and 201311102010.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201311102023) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2081622 + ... + 2176182.
It is an arithmetic number, because the mean of its divisors is an integer number (12652395600).
Almost surely, 2201311102022 is an apocalyptic number.
201311102022 is an abundant number, since it is smaller than the sum of its proper divisors (203565557178).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201311102022 is a wasteful number, since it uses less digits than its factorization.
201311102022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96548.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 201311102022 its reverse (220201113102), we get a palindrome (421512215124).
The spelling of 201311102022 in words is "two hundred one billion, three hundred eleven million, one hundred two thousand, twenty-two".
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