2013112021320 has 384 divisors, whose sum is σ = 6937767158400. Its totient is φ = 504838656000.

The previous prime is 2013112021231. The next prime is 2013112021357. The reversal of 2013112021320 is 231202113102.

2013112021320 is a `hidden beast` number, since 20 + 1 + 311 + 202 + 132 + 0 = 666.

It is a super-2 number, since 2×2013112021320² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 2013112021293 and 2013112021302.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 543935470 + ... + 543939170.

It is an arithmetic number, because the mean of its divisors is an integer number (18067101975).

Almost surely, 2^{2013112021320} is an apocalyptic number.

2013112021320 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2013112021320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3468883579200).

2013112021320 is an abundant number, since it is smaller than the sum of its proper divisors (4924655137080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2013112021320 is a wasteful number, since it uses less digits than its factorization.

2013112021320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4301 (or 4294 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 2013112021320 its reverse (231202113102), we get a palindrome (2244314134422).

The spelling of 2013112021320 in words is "two trillion, thirteen billion, one hundred twelve million, twenty-one thousand, three hundred twenty".