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20131123153 is a prime number
BaseRepresentation
bin10010101111111010…
…001000111111010001
31220221222021000101211
4102233322020333101
5312212031420103
613125331500121
71311603503101
oct225772107721
956858230354
1020131123153
1185a0548869
123a99a57641
131b8a8c76bb
14d8d899201
157cc51c36d
hex4afe88fd1

20131123153 has 2 divisors, whose sum is σ = 20131123154. Its totient is φ = 20131123152.

The previous prime is 20131123147. The next prime is 20131123183. The reversal of 20131123153 is 35132113102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18563517504 + 1567605649 = 136248^2 + 39593^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20131123153 is a prime.

It is a super-2 number, since 2×201311231532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20131123183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065561576 + 10065561577.

It is an arithmetic number, because the mean of its divisors is an integer number (10065561577).

Almost surely, 220131123153 is an apocalyptic number.

It is an amenable number.

20131123153 is a deficient number, since it is larger than the sum of its proper divisors (1).

20131123153 is an equidigital number, since it uses as much as digits as its factorization.

20131123153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 20131123153 its reverse (35132113102), we get a palindrome (55263236255).

The spelling of 20131123153 in words is "twenty billion, one hundred thirty-one million, one hundred twenty-three thousand, one hundred fifty-three".