Base | Representation |
---|---|
bin | 10010101111111010… |
… | …100000101011101011 |
3 | 1220221222102221112021 |
4 | 102233322200223223 |
5 | 312212043021303 |
6 | 13125333525311 |
7 | 1311604356043 |
oct | 225772405353 |
9 | 56858387467 |
10 | 20131220203 |
11 | 85a0604776 |
12 | 3a99aa3837 |
13 | 1b8a92c923 |
14 | d8d8c2723 |
15 | 7cc53aebd |
hex | 4afea0aeb |
20131220203 has 4 divisors (see below), whose sum is σ = 20825400240. Its totient is φ = 19437040168.
The previous prime is 20131220177. The next prime is 20131220227. The reversal of 20131220203 is 30202213102.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30202213102 = 2 ⋅15101106551.
It is a cyclic number.
It is not a de Polignac number, because 20131220203 - 25 = 20131220171 is a prime.
It is a super-2 number, since 2×201312202032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20131220273) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 347089975 + ... + 347090032.
It is an arithmetic number, because the mean of its divisors is an integer number (5206350060).
Almost surely, 220131220203 is an apocalyptic number.
20131220203 is a deficient number, since it is larger than the sum of its proper divisors (694180037).
20131220203 is an equidigital number, since it uses as much as digits as its factorization.
20131220203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 694180036.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 20131220203 its reverse (30202213102), we get a palindrome (50333433305).
The spelling of 20131220203 in words is "twenty billion, one hundred thirty-one million, two hundred twenty thousand, two hundred three".
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