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2013123012123 = 3671041004041
BaseRepresentation
bin11101010010110111011…
…110110110011000011011
321010110020000002221100010
4131102313132312120123
5230440333442341443
64140452124413003
7265305031160436
oct35226736663033
97113200087303
102013123012123
11706840505053
122861a69a7163
13117ab5275cc2
146d6156ba81d
153757512c733
hex1d4b77b661b

2013123012123 has 4 divisors (see below), whose sum is σ = 2684164016168. Its totient is φ = 1342082008080.

The previous prime is 2013123012059. The next prime is 2013123012149. The reversal of 2013123012123 is 3212103213102.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 2013123012123 - 26 = 2013123012059 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2013123012123.

It is not an unprimeable number, because it can be changed into a prime (2013123012323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335520502018 + ... + 335520502023.

It is an arithmetic number, because the mean of its divisors is an integer number (671041004042).

Almost surely, 22013123012123 is an apocalyptic number.

2013123012123 is a deficient number, since it is larger than the sum of its proper divisors (671041004045).

2013123012123 is an equidigital number, since it uses as much as digits as its factorization.

2013123012123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 671041004044.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 2013123012123 its reverse (3212103213102), we get a palindrome (5225226225225).

The spelling of 2013123012123 in words is "two trillion, thirteen billion, one hundred twenty-three million, twelve thousand, one hundred twenty-three".

Divisors: 1 3 671041004041 2013123012123