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2013123100113 = 33174385889107
BaseRepresentation
bin11101010010110111011…
…111001011110111010001
321010110020000021102001000
4131102313133023313101
5230440334003200423
64140452130332213
7265305032005116
oct35226737136721
97113200242030
102013123100113
11706840565174
122861a6a2a069
13117ab52a7078
146d61570090d
1537575148843
hex1d4b77cbdd1

2013123100113 has 16 divisors (see below), whose sum is σ = 3157840157760. Its totient is φ = 1263136062528.

The previous prime is 2013123100019. The next prime is 2013123100217. The reversal of 2013123100113 is 3110013213102.

It is not a de Polignac number, because 2013123100113 - 213 = 2013123091921 is a prime.

It is a super-2 number, since 2×20131231001132 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2013123150113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2192944095 + ... + 2192945012.

It is an arithmetic number, because the mean of its divisors is an integer number (197365009860).

Almost surely, 22013123100113 is an apocalyptic number.

It is an amenable number.

2013123100113 is a deficient number, since it is larger than the sum of its proper divisors (1144717057647).

2013123100113 is a wasteful number, since it uses less digits than its factorization.

2013123100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4385889133 (or 4385889127 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 2013123100113 its reverse (3110013213102), we get a palindrome (5123136313215).

The spelling of 2013123100113 in words is "two trillion, thirteen billion, one hundred twenty-three million, one hundred thousand, one hundred thirteen".

Divisors: 1 3 9 17 27 51 153 459 4385889107 13157667321 39473001963 74560114819 118419005889 223680344457 671041033371 2013123100113