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2013130113 = 36111000711
BaseRepresentation
bin111011111111101…
…1110110110000001
312012022001121100120
41313333132312001
513110330130423
6531432210453
7100613216001
oct16777366601
95168047316
102013130113
119433a54a5
12482239a29
132610c3867
14151516001
15bbb07ee3
hex77fded81

2013130113 has 8 divisors (see below), whose sum is σ = 2728176576. Its totient is φ = 1320085200.

The previous prime is 2013130109. The next prime is 2013130127. The reversal of 2013130113 is 3110313102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2013130113 - 22 = 2013130109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2013130092 and 2013130101.

It is not an unprimeable number, because it can be changed into a prime (2013130193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5500173 + ... + 5500538.

It is an arithmetic number, because the mean of its divisors is an integer number (341022072).

Almost surely, 22013130113 is an apocalyptic number.

It is an amenable number.

2013130113 is a deficient number, since it is larger than the sum of its proper divisors (715046463).

2013130113 is a wasteful number, since it uses less digits than its factorization.

2013130113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11000775.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 2013130113 is about 44867.9185276072. The cubic root of 2013130113 is about 1262.6721891472.

Adding to 2013130113 its reverse (3110313102), we get a palindrome (5123443215).

The spelling of 2013130113 in words is "two billion, thirteen million, one hundred thirty thousand, one hundred thirteen".

Divisors: 1 3 61 183 11000711 33002133 671043371 2013130113