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2013133331203 is a prime number
BaseRepresentation
bin11101010010111000000…
…110001101101100000011
321010110020201112012110021
4131102320012031230003
5230440344113044303
64140453133514311
7265305214656301
oct35227006155403
97113221465407
102013133331203
11706846312a15
122861aa342997
13117ab7449b77
146d616c05271
1537575eb9ebd
hex1d4b818db03

2013133331203 has 2 divisors, whose sum is σ = 2013133331204. Its totient is φ = 2013133331202.

The previous prime is 2013133331173. The next prime is 2013133331213. The reversal of 2013133331203 is 3021333313102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2013133331203 - 25 = 2013133331171 is a prime.

It is a super-4 number, since 4×20131333312034 (a number of 50 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (2013133331213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006566665601 + 1006566665602.

It is an arithmetic number, because the mean of its divisors is an integer number (1006566665602).

Almost surely, 22013133331203 is an apocalyptic number.

2013133331203 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013133331203 is an equidigital number, since it uses as much as digits as its factorization.

2013133331203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 2013133331203 its reverse (3021333313102), we get a palindrome (5034466644305).

The spelling of 2013133331203 in words is "two trillion, thirteen billion, one hundred thirty-three million, three hundred thirty-one thousand, two hundred three".