Base | Representation |
---|---|
bin | 11101010010111000100… |
… | …001110000111001101011 |
3 | 21010110021020010010100012 |
4 | 131102320201300321223 |
5 | 230440402440201243 |
6 | 4140453552402135 |
7 | 265305333236114 |
oct | 35227041607153 |
9 | 7113236103305 |
10 | 2013140553323 |
11 | 70684a3a6009 |
12 | 2861b084634b |
13 | 117ab8aa8203 |
14 | 6d617b6520b |
15 | 37576944d18 |
hex | 1d4b8870e6b |
2013140553323 has 4 divisors (see below), whose sum is σ = 2013456148440. Its totient is φ = 2012824958208.
The previous prime is 2013140553313. The next prime is 2013140553379. The reversal of 2013140553323 is 3233550413102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2013140553323 - 230 = 2012066811499 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2013140553323.
It is not an unprimeable number, because it can be changed into a prime (2013140553313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157787990 + ... + 157800747.
It is an arithmetic number, because the mean of its divisors is an integer number (503364037110).
Almost surely, 22013140553323 is an apocalyptic number.
2013140553323 is a deficient number, since it is larger than the sum of its proper divisors (315595117).
2013140553323 is an equidigital number, since it uses as much as digits as its factorization.
2013140553323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 315595116.
The product of its (nonzero) digits is 32400, while the sum is 32.
Adding to 2013140553323 its reverse (3233550413102), we get a palindrome (5246690966425).
The spelling of 2013140553323 in words is "two trillion, thirteen billion, one hundred forty million, five hundred fifty-three thousand, three hundred twenty-three".
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