Base | Representation |
---|---|
bin | 11101010010111000101… |
… | …011110111010100100001 |
3 | 21010110021102002122100102 |
4 | 131102320223313110201 |
5 | 230440404124413212 |
6 | 4140454125232145 |
7 | 265305364604342 |
oct | 35227053672441 |
9 | 7113242078312 |
10 | 2013143201057 |
11 | 70685094431a |
12 | 2861b1702655 |
13 | 117ab94c4411 |
14 | 6d6182540c9 |
15 | 37576cb95c2 |
hex | 1d4b8af7521 |
2013143201057 has 2 divisors, whose sum is σ = 2013143201058. Its totient is φ = 2013143201056.
The previous prime is 2013143201053. The next prime is 2013143201093. The reversal of 2013143201057 is 7501023413102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1043832065761 + 969311135296 = 1021681^2 + 984536^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013143201057 - 22 = 2013143201053 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013143201053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006571600528 + 1006571600529.
It is an arithmetic number, because the mean of its divisors is an integer number (1006571600529).
Almost surely, 22013143201057 is an apocalyptic number.
It is an amenable number.
2013143201057 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013143201057 is an equidigital number, since it uses as much as digits as its factorization.
2013143201057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 2013143201057 its reverse (7501023413102), we get a palindrome (9514166614159).
The spelling of 2013143201057 in words is "two trillion, thirteen billion, one hundred forty-three million, two hundred one thousand, fifty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •