Base | Representation |
---|---|
bin | 1011101101111110011… |
… | …1010101010000000011 |
3 | 201020122100100000011100 |
4 | 2323133213111100003 |
5 | 11244300423003233 |
6 | 232252444545443 |
7 | 20354620555143 |
oct | 2733747252003 |
9 | 636570300140 |
10 | 201320125443 |
11 | 78419a64a68 |
12 | 33025852283 |
13 | 15ca49826a8 |
14 | 9a5b560923 |
15 | 53842dc813 |
hex | 2edf9d5403 |
201320125443 has 12 divisors (see below), whose sum is σ = 291077802288. Its totient is φ = 134083232880.
The previous prime is 201320125441. The next prime is 201320125477. The reversal of 201320125443 is 344521023102.
201320125443 is a `hidden beast` number, since 2 + 0 + 13 + 201 + 2 + 5 + 443 = 666.
It is not a de Polignac number, because 201320125443 - 21 = 201320125441 is a prime.
It is not an unprimeable number, because it can be changed into a prime (201320125441) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10838880 + ... + 10857437.
It is an arithmetic number, because the mean of its divisors is an integer number (24256483524).
Almost surely, 2201320125443 is an apocalyptic number.
201320125443 is a deficient number, since it is larger than the sum of its proper divisors (89757676845).
201320125443 is a wasteful number, since it uses less digits than its factorization.
201320125443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21697354 (or 21697351 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 201320125443 its reverse (344521023102), we get a palindrome (545841148545).
The spelling of 201320125443 in words is "two hundred one billion, three hundred twenty million, one hundred twenty-five thousand, four hundred forty-three".
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