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2013202123 is a prime number
BaseRepresentation
bin111011111111111…
…0000011011001011
312012022012021010121
41313333300123023
513110334431443
6531433524111
7100613635642
oct16777603313
95168167117
102013202123
11943444609
12482273637
1326111a57a
14151534359
15bbb1e4ed
hex77ff06cb

2013202123 has 2 divisors, whose sum is σ = 2013202124. Its totient is φ = 2013202122.

The previous prime is 2013202099. The next prime is 2013202129. The reversal of 2013202123 is 3212023102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2013202123 - 25 = 2013202091 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2013202097 and 2013202106.

It is not a weakly prime, because it can be changed into another prime (2013202129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006601061 + 1006601062.

It is an arithmetic number, because the mean of its divisors is an integer number (1006601062).

Almost surely, 22013202123 is an apocalyptic number.

2013202123 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013202123 is an equidigital number, since it uses as much as digits as its factorization.

2013202123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 2013202123 is about 44868.7209868969. The cubic root of 2013202123 is about 1262.6872442994.

Adding to 2013202123 its reverse (3212023102), we get a palindrome (5225225225).

The spelling of 2013202123 in words is "two billion, thirteen million, two hundred two thousand, one hundred twenty-three".