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2013202230019 is a prime number
BaseRepresentation
bin11101010010111100001…
…101000010101100000011
321010110102112011121212021
4131102330031002230003
5230441014232330034
64140504034342311
7265310012415421
oct35227415025403
97113375147767
102013202230019
117068811a1692
1228620942a997
13117ac87c13b6
146d62201c111
153757c0796b4
hex1d4bc342b03

2013202230019 has 2 divisors, whose sum is σ = 2013202230020. Its totient is φ = 2013202230018.

The previous prime is 2013202230007. The next prime is 2013202230023. The reversal of 2013202230019 is 9100322023102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2013202230019 - 235 = 1978842491651 is a prime.

It is a super-2 number, since 2×20132022300192 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2013202229975 and 2013202230002.

It is not a weakly prime, because it can be changed into another prime (2013202230119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006601115009 + 1006601115010.

It is an arithmetic number, because the mean of its divisors is an integer number (1006601115010).

Almost surely, 22013202230019 is an apocalyptic number.

2013202230019 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013202230019 is an equidigital number, since it uses as much as digits as its factorization.

2013202230019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

The spelling of 2013202230019 in words is "two trillion, thirteen billion, two hundred two million, two hundred thirty thousand, nineteen".