Base | Representation |
---|---|
bin | 11101010010111100001… |
… | …101000101001011010011 |
3 | 21010110102112012010211202 |
4 | 131102330031011023103 |
5 | 230441014233141321 |
6 | 4140504034501415 |
7 | 265310012460221 |
oct | 35227415051323 |
9 | 7113375163752 |
10 | 2013202240211 |
11 | 7068811a9308 |
12 | 28620943486b |
13 | 117ac87c5c26 |
14 | 6d622021b11 |
15 | 3757c07c70b |
hex | 1d4bc3452d3 |
2013202240211 has 2 divisors, whose sum is σ = 2013202240212. Its totient is φ = 2013202240210.
The previous prime is 2013202240201. The next prime is 2013202240229. The reversal of 2013202240211 is 1120422023102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013202240211 - 210 = 2013202239187 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013202240201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006601120105 + 1006601120106.
It is an arithmetic number, because the mean of its divisors is an integer number (1006601120106).
Almost surely, 22013202240211 is an apocalyptic number.
2013202240211 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013202240211 is an equidigital number, since it uses as much as digits as its factorization.
2013202240211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 2013202240211 its reverse (1120422023102), we get a palindrome (3133624263313).
The spelling of 2013202240211 in words is "two trillion, thirteen billion, two hundred two million, two hundred forty thousand, two hundred eleven".
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