Base | Representation |
---|---|
bin | 11101010010111100101… |
… | …110100010110000011011 |
3 | 21010110110010200210122101 |
4 | 131102330232202300123 |
5 | 230441024004341443 |
6 | 4140504550504231 |
7 | 265310150153263 |
oct | 35227456426033 |
9 | 7113403623571 |
10 | 2013211012123 |
11 | 70688614a823 |
12 | 286210365077 |
13 | 117aca5777cc |
14 | 6d6232667a3 |
15 | 3757cc1184d |
hex | 1d4bcba2c1b |
2013211012123 has 2 divisors, whose sum is σ = 2013211012124. Its totient is φ = 2013211012122.
The previous prime is 2013211012117. The next prime is 2013211012151. The reversal of 2013211012123 is 3212101123102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013211012123 - 213 = 2013211003931 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2013211012123.
It is not a weakly prime, because it can be changed into another prime (2013211012523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006605506061 + 1006605506062.
It is an arithmetic number, because the mean of its divisors is an integer number (1006605506062).
Almost surely, 22013211012123 is an apocalyptic number.
2013211012123 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013211012123 is an equidigital number, since it uses as much as digits as its factorization.
2013211012123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2013211012123 its reverse (3212101123102), we get a palindrome (5225312135225).
The spelling of 2013211012123 in words is "two trillion, thirteen billion, two hundred eleven million, twelve thousand, one hundred twenty-three".
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