Search a number
-
+
20132201302033 = 83172420608549
BaseRepresentation
bin1001001001111011001001…
…01101010000100000010001
32122021121201201112110222111
410210331210231100200101
510114321222013131113
6110452334450505321
74145334500400262
oct444754455204021
978247651473874
1020132201302033
116462022875a47
122311909595241
13b305c6254742
144d8591c22969
1524da410c213d
hex124f64b50811

20132201302033 has 4 divisors (see below), whose sum is σ = 20134621918900. Its totient is φ = 20129780685168.

The previous prime is 20132201302027. The next prime is 20132201302039. The reversal of 20132201302033 is 33020310223102.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (20132201302027) and next prime (20132201302039).

It can be written as a sum of positive squares in 2 ways, for example, as 19656250330369 + 475950971664 = 4433537^2 + 689892^2 .

It is a cyclic number.

It is not a de Polignac number, because 20132201302033 - 221 = 20132199204881 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20132201301995 and 20132201302013.

It is not an unprimeable number, because it can be changed into a prime (20132201302039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1210295958 + ... + 1210312591.

It is an arithmetic number, because the mean of its divisors is an integer number (5033655479725).

Almost surely, 220132201302033 is an apocalyptic number.

It is an amenable number.

20132201302033 is a deficient number, since it is larger than the sum of its proper divisors (2420616867).

20132201302033 is an equidigital number, since it uses as much as digits as its factorization.

20132201302033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2420616866.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 20132201302033 its reverse (33020310223102), we get a palindrome (53152511525135).

The spelling of 20132201302033 in words is "twenty trillion, one hundred thirty-two billion, two hundred one million, three hundred two thousand, thirty-three".

Divisors: 1 8317 2420608549 20132201302033